Python loc id in list

In [30]: df = pd.DataFrame({'subscriber_id':[1,2,3,4,5]})
'''   	subscriber_id
	0              1
	1              2
	2              3
	3              4
	4              5 '''

mask = df['subscriber_id'].isin([2,4,5])
''' 0    False
	1     True
	2    False
	3     True
	4     True '''

df.loc[mask]
'''	   subscriber_id
	1              2
	3              4
	4              5 '''

Source: stackoverflow.com

Similar codes

2 votes265 views1 answer
Json dumps datetime
Python
21 votes203 views4 answers
Floor function in python
Python
0 vote210 views1 answer
Python pyowm
Python
2 votes204 views1 answer
Python type of column
Python
1 vote221 views1 answer
Pytz
Python
1 vote211 views1 answer
How to fix turtle has no member
Python
0 vote204 views1 answer
Python open file exception
Python
0 vote199 views1 answer
Rest plus
Python
0 vote214 views1 answer
Extract all bounding boxes using OpenCV Python
Python
0 vote214 views1 answer
Run exe for python and wait until finish
Python