Return char array in c

Accessing the elements of a char* in c

#include <stdio.h>

int main()
{
    char *p="abcd";
    printf("%c\n", p[0]);
    printf("%c\n", p[1]);
    printf("%c\n", p[2]);
    printf("%c\n", p[3]);
    return 0;
}

Source: stackoverflow.com

How to return array of char in c

char *foo(int count) {
    char *ret = malloc(count);
    if(!ret)
        return NULL;

    for(int i = 0; i < count; ++i) 
        ret[i] = i;

    return ret;
}

Source: stackoverflow.com

How to return array of char in c

int main() {
    char *p = foo(10);
    if(p) {
        // do stuff with p
        free(p);
    }

    return 0;
}

Source: stackoverflow.com

Return char array in c

char * createStr() {

    char char1= 'm';
    char char2= 'y';

    char *str = malloc(3);
    str[0] = char1;
    str[1] = char2;
    str[2] = '\0';

    return str;

}

-1

Source: stackoverflow.com

How to return a char array from a function in C

#include <stdio.h>
#include <string.h>
    char* createStr(){
    static char str[20] = "my";
    return str;
}
int main(){
    char a[20];
    strcpy(a,createStr()); //this will copy the returned value of createStr() into a[]
    printf("%s",a);
    return 0;
}

-2

Source: stackoverflow.com

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