/Python/Flask/How to close a flask web server with python

How to close a flask web server with python

from flask import Flask, request, jsonify

# Workaround - otherwise doesn't work in windows service.
cli = sys.modules['flask.cli']
cli.show_server_banner = lambda *x: None

app = Flask('MyService')

# ... business logic endpoints are skipped.

@app.route("/shutdown", methods=['GET'])
def shutdown():
    shutdown_func = request.environ.get('werkzeug.server.shutdown')
    if shutdown_func is None:
        raise RuntimeError('Not running werkzeug')
    shutdown_func()
    return "Shutting down..."


def start():
    app.run(host='0.0.0.0', threaded=True, port=5001)


def stop():
    import requests
    resp = requests.get('http://localhost:5001/shutdown')

Source: stackoverflow.com

How to close a flask web server with python

from multiprocessing import Process

server = Process(target=app.run)
server.start()
# ...
server.terminate()
server.join()

Source: stackoverflow.com

Similar codes

0 vote301 views1 answer
Flask return 404
Python Flask
3 votes296 views1 answer
Flask upload
Python Flask
6 votes307 views3 answers
Flask client ip
Python Flask
0 vote330 views1 answer
How to send image to template thats not in static flask
Python Flask
0 vote324 views1 answer
Flask recive list
Python Flask
3 votes317 views1 answer
Default argument in flask route
Python Flask
0 vote290 views1 answer
Flask print request headers
Python Flask
-1 vote324 views1 answer
Flask set mime type
Python Flask
1 vote383 views1 answer
Flask enumerate index
Python Flask
0 vote371 views1 answer
Problems with flask bootstrap
Python Flask