/Python/Return position of a unique value in python array

Return position of a unique value in python array

In [304]: array = np.array([1, 1, 2, 3, 2, 1, 2, 3])

In [305]: np.unique(array)            # unique values in `array`
Out[305]: array([1, 2, 3])

In [306]: array == 1                  # retrieve a boolean mask where elements are equal to 1
Out[306]: array([ True,  True, False, False, False,  True, False, False])

In [307]: (array == 1).nonzero()[0]   # get the `True` indices for the operation above
Out[307]: array([0, 1, 5])

Source: stackoverflow.com

Similar codes

0 vote273 views1 answer
Get the time of 1 minute later in python
Python
110 votes291 views6 answers
Python while
Python
0 vote274 views1 answer
Gui def python
Python
1 vote277 views2 answers
Replace number with string python
Python
0 vote311 views1 answer
Argumrnt with reverse django
Python Django
1 vote256 views1 answer
Codeforces - 570b python
Python
0 vote284 views1 answer
Numpy get length of list
Python
0 vote314 views1 answer
Custom permission class django rest framework
Python Django
101 votes192 views10 answers
Read files python
Python
0 vote275 views2 answers
Get the first item from an iterable that matches a condition
Python