/SQL/Postgresql difference between two dates in days

Postgresql difference between two dates in days

Postgresql get difference in hours between two dates

select EXTRACT(
	EPOCH FROM now() - (now() - INTERVAL '5 HOUR')
)/3600

-- it will return 5

Source: stackoverflow.com

Postgresql difference between two dates in days

SELECT
  AGE('2012-03-05', '2010-04-01'),
  DATE_PART('year', AGE('2012-03-05', '2010-04-01')) AS years,
  DATE_PART('month', AGE('2012-03-05', '2010-04-01')) AS months,
  DATE_PART('day', AGE('2012-03-05', '2010-04-01')) AS days;
 
...  
-- This will give you full years, month, days ... between two dates:

--          age          | years | months | days
-- -----------------------+-------+--------+------
--  1 year 11 mons 4 days |     1 |     11 |    4

Source: stackoverflow.com

DATEDIFF minute postgres

  -- Difference between Dec 30, 2011 08:54:55 and  Dec 30, 2011 08:56:10 in minutes
  SELECT (DATE_PART('day', '2011-12-30 08:56:10'::timestamp - '2011-12-30 08:54:55'::timestamp) * 24 * 60 + 
               DATE_PART('hour', '2011-12-30 08:56:10'::timestamp - '2011-12-30 08:54:55'::timestamp)) * 60 +
               DATE_PART('minute', '2011-12-30 08:56:10'::timestamp - '2011-12-30 08:54:55'::timestamp);
  -- Result: 1
 
  -- Time only
  SELECT DATE_PART('hour', '08:56:10'::time - '08:54:55'::time) * 60 +
              DATE_PART('minute', '08:56:10'::time - '08:54:55'::time);
  -- Result: 1

Source: sqlines.com

Postgresql get diff between two dates in Months

EXTRACT(year FROM age(end_date,start_date))*12 + EXTRACT(month FROM age(end_date,start_date))

Source: lexykassan.com

Postgresql get difference between two dates

select age('2010-04-01', '2012-03-05'),
       date_part('year',age('2010-04-01', '2012-03-05')),
       date_part('month',age('2010-04-01', '2012-03-05')),
       date_part('day',age('2010-04-01', '2012-03-05'));

-1

Source: stackoverflow.com

Similar codes

5 votes190 views1 answer
Oracle columns in all_tables
SQL
0 vote190 views1 answer
ERROR: column "hourly_visitors.hour" must appear in the GROUP BY clause or be used in an aggregate function
SQL
0 vote204 views1 answer
Postgresql interview questions
SQL
0 vote195 views1 answer
What are the advantages of MySQL when compared with Oracle?
SQL
1 vote199 views1 answer
Use of now() in mysql
SQL
0 vote216 views1 answer
Find the names of sailors who have reserved a red boat, and list in the order of age
SQL
0 vote206 views1 answer
Sql server get date of previous sunday
SQL
3 votes148 views1 answer
If 0 return null else return query mysql
SQL
0 vote173 views1 answer
Mql5 list all available symbols
SQL
0 vote182 views1 answer
Sql random decimal
SQL