/Python/Python code for create diamond shape with integer

Python code for create diamond shape with integer

n = 9
print("Pattern 1")
for a1 in range(1, (n+1)//2 + 1): #from row 1 to 5
    for a2 in range((n+1)//2 - a1):
        print(" ", end = "")
    for a3 in range((a1*2)-1):
        print("*", end = "")
    print()

for a1 in range((n+1)//2 + 1, n + 1): #from row 6 to 9
    for a2 in range(a1 - (n+1)//2):
        print(" ", end = "")
    for a3 in range((n+1 - a1)*2 - 1):
        print("*", end = "")
    print()

Source: stackoverflow.com

Diamond shape in python

def p(n):
    for i in range(n):
        print(" "*(n-i-1),end="")
        print("* "*(i+1))
        
    for j in range(n-1, 0, -1):
        print(" "*(n-j),end="")
        print("* "*(j))

star_num = int(input("Enter a number that shows diameters of your diamond shape: "))
print(p(star_num))

Similar codes

0 vote189 views2 answers
Hi i smell like poop
Python
1 vote190 views3 answers
Link in embed discord.py
Python
60 votes197 views6 answers
Python remove letters from string
Python
0 vote208 views1 answer
How to bubble search in python stack overflow
Python
0 vote182 views1 answer
Pass context data with templateview in django
Python
0 vote198 views1 answer
Pandas select only earliest event for duplicates
Python
3 votes187 views2 answers
Auticlicker python
Python
3 votes222 views1 answer
Flask secret key generator
Python Flask
0 vote184 views1 answer
Python for skip header line
Python
0 vote208 views1 answer
Change edit last line python
Python