Pandas select row by index

How to get a row from a dataframe in python

df.iloc[[index]]

Source: stackoverflow.com

Pandas select row by index

#for single row
df.loc[ index , : ]

# for multiple rows
indices = [1, 20, 33, 47, 52 ]
new_df= df.iloc[indices, :]

Dataframe get row by name

row_data = df.loc[ 'a' , : ]

Source: thispointer.com

Isolate row based on index pandas

dfObj.iloc[: , [0, 2]]

Source: thispointer.com

Select rows from dataframe pandas

from pandas import DataFrame

boxes = {'Color': ['Green','Green','Green','Blue','Blue','Red','Red','Red'],
         'Shape': ['Rectangle','Rectangle','Square','Rectangle','Square','Square','Square','Rectangle'],
         'Price': [10,15,5,5,10,15,15,5]
        }

df = DataFrame(boxes, columns= ['Color','Shape','Price'])

select_color = df.loc[df['Color'] == 'Green']
print (select_color)

Source: datatofish.com

Pandas df by row index

indices = [133, 22, 19, 203, 14, 1]
df_by_indices = df.iloc[indices, :]

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