Python try

How to print error in try except python

try:
  # some code
except Exception as e:
	print("ERROR : "+str(e))

Python try except

import sys

try:
    f = open('myfile.txt')
    s = f.readline()
    i = int(s.strip())
except OSError as err:
    print("OS error: {0}".format(err))
except ValueError:
    print("Could not convert data to an integer.")
except:
    print("Unexpected error:", sys.exc_info()[0])
    raise

Print type of exception python

try:
    someFunction()
except Exception as ex:
    template = "An exception of type {0} occurred. Arguments:\n{1!r}"
    message = template.format(type(ex).__name__, ex.args)
    print (message)

Source: stackoverflow.com

Python try except

try:
  val = 1/0 
except Exception as e:
  raise Exception('ZeroDivisionError')

Try except python

try:
    Age = int(input("Your Age:- "))
except ValueError:
    print("Age not in Intger form")

Python try

try:
    print(x)
except:
    print("Err")

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