Pronic number program in python

n = int(input("Enter a number: "))
f = 0
for i in range(n):
    if i * (i + 1) == n:
        f = 1
        break

if f==1:
    print("Pronic number")
else:
    print("Not a Pronic number")

Source: codespeedy.com

Similar codes

0 vote150 views1 answer
Kivy bind when text changes
Python
0 vote169 views1 answer
Python find if strings have common substring
Python
0 vote177 views1 answer
Panda datetime ymd to dmy
Python
0 vote174 views1 answer
Integer to boolean numpy
Python
32 votes166 views3 answers
Read csv python pandas plot
Python
0 vote163 views1 answer
Python reading csv files from web
Python
3 votes190 views2 answers
How to find word in file python
Python
17 votes167 views6 answers
Print function in python
Python
4 votes159 views3 answers
List element swapping python
Python
4 votes179 views4 answers
Printing hello world in python
Python