/Shell/Bash/Bash get one checksum for many files

Bash get one checksum for many files

# Basic syntax:
find /directory/to/search -type f -exec md5sum {} + | awk '{print $1}' | sort | md5sum > single_md5sum.txt

# Where:
#	- find -type f returns all files (but not directories) in 
#		/directory/to/search and its subdirectories
#	- -exec md5sum {} obtains the md5 checksums for all files returned 
#		with find
#	- awk '{print $1}' | sort returns the sorted md5 checksums
#	- and finally, md5sum is run on the sorted list of md5 checksums to
#		return one md5 checksum for all the files

Bash how to generate md5 checksums on all files in a directory

# Basic syntax:
md5sum /path/to/directory/* > list_of_checksums

# Note, md5sum will run on any files that are found with your search
# 	pattern. For example:
md5sum /path/*/*files_I_want* > list_of_checksums
# This would process all files than contain the substring "files_I_want"
# in all directories in the "path" directory

Source: askubuntu.com

Similar codes

0 vote197 views1 answer
Count unique ip addresses linux accsses log
Shell/Bash
69 votes208 views1 answer
Git override remote origin
Shell/Bash
1 vote188 views2 answers
Tmux commands
Shell/Bash
1 vote181 views1 answer
Powershell Core server manager module
Shell/Bash
0 vote187 views1 answer
Sed insert multiple lines after match
Shell/Bash
2 votes205 views1 answer
Git track filename capitalisation
Shell/Bash
4 votes162 views1 answer
Show path in terminal linux
Shell/Bash
0 vote201 views2 answers
Sudo passwordless
Shell/Bash
3 votes186 views1 answer
Powershell if operator
Shell/Bash
0 vote204 views1 answer
Git reset back to previous pushed commit
Shell/Bash