Sort the dictionary in python

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Python sort dictionary by key

In [1]: import collections

In [2]: d = {2:3, 1:89, 4:5, 3:0}

In [3]: od = collections.OrderedDict(sorted(d.items()))

In [4]: od
Out[4]: OrderedDict([(1, 89), (2, 3), (3, 0), (4, 5)])

Source: stackoverflow.com

Sort the dictionary in python

d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)

Python sort dictionary by key

def sort_dict(dictionary, rev = True):
    l = list(dictionary.items())
    l.sort(reverse = rev)
    a = [item[1] for item in l]    
    z = ''    
    for x in a:
        z = z + str(x)
    return(z)

Sorting values in dictionary in python

#instead of using python inbuilt function we can it compute directly.
#here iam sorting the values in descending order..
d = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
s=[]
for i in d.items():
  s.append(i)
for i in range(0,len(s)):
  for j in range(i+1,len(s)):
    if s[i][1]<s[j][1]:
      s[i],s[j]=s[j],s[i]
print(dict(s))

Similar codes

236 votes378 views6 answers
Import random in python
Python
1 vote168 views1 answer
Placeholder tkinter
Python
0 vote159 views1 answer
Loop through list, find specific number and output element's index
Python
2 votes180 views4 answers
ValueError: Input contains NaN, infinity or a value too large for dtype('float32'). site:stackoverflow.com
Python
0 vote160 views1 answer
Login_required
Python
0 vote175 views1 answer
Standardscaler
Python
3 votes127 views1 answer
Torch view
Python
4 votes175 views2 answers
Pandas most frequent value
Python
0 vote179 views1 answer
Unused import statement 'from tkinter import *'
Python
9 votes170 views5 answers
Threading python
Python