Python .findall

  ## Search for pattern 'bb' in string 'aabbcc'.
  ## All of the pattern must match, but it may appear anywhere.
  ## On success, match.group() is matched text.
  match = re.search(r'bb', 'aabbcc') # found, match.group() == "bb"
  match = re.search(r'cd', 'aabbcc') # not found, match == None

  ## . = any char but \n
  match = re.search(r'...c', 'aabbcc') # found, match.group() == "abbc"

  ## \d = digit char, \w = word char
  match = re.search(r'\d\d\d', 'p123g') # found, match.group() == "123"
  match = re.search(r'\w\w\w', '@@abcd!!') # found, match.group() == "abc"

Similar codes

0 vote281 views1 answer
Facet grid, barplot, catplot
Python
0 vote327 views1 answer
Django cleanup settings
Python Django
0 vote301 views1 answer
Dataframe string find count
Python
0 vote292 views1 answer
Renpy quickstart
Python
-1 vote308 views2 answers
Dd-mm-yy to yyyy-mm-dd in python
Python
0 vote313 views1 answer
Replit python keep discord bot online
Python
0 vote303 views1 answer
If condition in python 1
Python
1 vote295 views1 answer
.replit file python
Python
0 vote337 views1 answer
Abstract user in django
Python Django
1 vote270 views1 answer
How to remove seconds from datetime in python
Python