Python .findall

  ## Search for pattern 'bb' in string 'aabbcc'.
  ## All of the pattern must match, but it may appear anywhere.
  ## On success, match.group() is matched text.
  match = re.search(r'bb', 'aabbcc') # found, match.group() == "bb"
  match = re.search(r'cd', 'aabbcc') # not found, match == None

  ## . = any char but \n
  match = re.search(r'...c', 'aabbcc') # found, match.group() == "abbc"

  ## \d = digit char, \w = word char
  match = re.search(r'\d\d\d', 'p123g') # found, match.group() == "123"
  match = re.search(r'\w\w\w', '@@abcd!!') # found, match.group() == "abc"

Similar codes

7 votes325 views1 answer
Python Emoji
Python
0 vote360 views1 answer
Then generate Django project from the project template of cookiecutter
Python
0 vote421 views1 answer
No module named 'django_hitcounter'
Python Django
5 votes313 views3 answers
Tuplein python
Python
-86 votes339 views10 answers
Code
Python
0 vote364 views2 answers
Isinstance in python
Python
0 vote302 views1 answer
Python datetime subtract seconds
Python
0 vote319 views1 answer
Nibabel expand dimension
Python
8 votes365 views6 answers
Python functions
Python
15 votes343 views3 answers
Python random text generator
Python