For row in column pandas

df = pd.DataFrame([{'c1':10, 'c2':100}, {'c1':11,'c2':110}, {'c1':12,'c2':120}])
for index, row in df.iterrows():
    print(row['c1'], row['c2'])

Source: stackoverflow.com

Python - iterate with the data frame

# Option 1
for row in df.iterrows():
    print row.loc[0,'A']
    print row.A
    print row.index()

# Option 2
for i in range(len(df)) : 
  print(df.iloc[i, 0], df.iloc[i, 2])

Source: stackoverflow.com

Similar codes

18 votes130 views1 answer
Convert column in pandas to datetime
Python
5 votes123 views2 answers
Conda install spacy
Python
0 vote106 views1 answer
Download python 3.8
Python
2 votes114 views1 answer
Np.pad
Python
0 vote123 views1 answer
Simple Splash screen in pyqt5
Python
1 vote108 views1 answer
Remove consecutive duplicates python
Python
0 vote122 views1 answer
Python cron job virtualenv
Python
9 votes112 views3 answers
Pyramid pattern in python
Python
0 vote117 views1 answer
Invalid literal for int() with base 10 python
Python
0 vote93 views1 answer
Download viper for python ubutunu
Python