Flask api with parameter

args = request.args
print (args) # For debugging
no1 = args['key1']
no2 = args['key2']
return jsonify(dict(data=[no1, no2])) # or whatever is required

Source: stackoverflow.com

Similar codes

0 vote350 views1 answer
How to return an html file in flask
Python Flask
0 vote344 views2 answers
Flask rest api upload image
Python Flask
6 votes339 views2 answers
Flask get ip address of request
Python Flask
5 votes356 views1 answer
Python flask query params
Python Flask
1 vote344 views1 answer
Procfile flask
Python Flask
0 vote334 views1 answer
Flask app with spark
Python Flask
0 vote297 views1 answer
Flask debugtoolbar
Python Flask
0 vote385 views1 answer
Flask No application found. Either work inside a view function or push an application context
Python Flask
15 votes366 views6 answers
Flask install
Python Flask
3 votes343 views3 answers
Flask migrate
Python Flask