Flask api with parameter

args = request.args
print (args) # For debugging
no1 = args['key1']
no2 = args['key2']
return jsonify(dict(data=[no1, no2])) # or whatever is required

Source: stackoverflow.com

Similar codes

0 vote131 views1 answer
How to set and run flask app on terminal
Python Flask
0 vote157 views1 answer
How to pre populate field flask wtforms
Python Flask
0 vote133 views1 answer
Flash not defined python flask
Python Flask
1 vote131 views1 answer
Flask socketio usage
Python Flask
0 vote149 views2 answers
Flask get summernote text
Python Flask
0 vote82 views1 answer
Jinja flask
Python Flask
0 vote143 views1 answer
PermissionError: [Errno 13] Permission denied on flask
Python Flask
4 votes138 views2 answers
Flask arguments in url
Python Flask
1 vote133 views2 answers
Flask console log
Python Flask
0 vote139 views2 answers
Flask socket io
Python Flask