Python replace by dictionary

address = "123 north anywhere street"

for word, initial in {"NORTH":"N", "SOUTH":"S" }.items():
    address = address.replace(word.lower(), initial)
print address

Source: stackoverflow.com

Replace key of dictionary python

a_dict = {"a": 1, "B": 2, "C": 3}

new_key = "A"
old_key = "a"
a_dict[new_key] = a_dict.pop(old_key)

print(a_dict)
OUTPUT
{'B': 2, 'C': 3, 'A': 1}

Similar codes

6 votes281 views2 answers
Tkinter template
Python
0 vote291 views1 answer
Python sqlobject declare connection
Python
1 vote300 views1 answer
Flask define template folder
Python
2 votes310 views1 answer
Search code ascii python
Python
2 votes317 views2 answers
Python split string capital letters
Python
0 vote276 views1 answer
Dockerize django app
Python
0 vote324 views1 answer
No module named 'django_hitcounter'
Python
2 votes287 views1 answer
Test_size
Python
6 votes303 views2 answers
Slice dataframe pandas based on condition
Python
1 vote309 views1 answer
Str replace python regex
Python