/Python/How to find if a value is even or odd in python

How to find if a value is even or odd in python

How to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))

Source: javatpoint.com

How to find if a value is even or odd in python

num = int(input("Enter a Number:"))
if num % 2 == 0:
  print(num , "is even")
else:
  print(num , "is odd")

Odd or even in python

n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")

Similar codes

0 vote218 views1 answer
Scipy version check
Python
0 vote212 views1 answer
TypeError: Object of type DictProxy is not JSON serializable
Python
0 vote220 views1 answer
Can we use python functions in node
Python
0 vote220 views1 answer
How to assign a new value in a column in pandas dataframe
Python
13 votes202 views3 answers
Python memory usage
Python
0 vote214 views1 answer
Somalia embassy in bangladesh
Python
0 vote212 views1 answer
How to make a var in pycode
Python
0 vote229 views1 answer
Merge two Querysets in Python Django while preserving Queryset methods
Python
0 vote213 views1 answer
How to parse timestamp in python
Python
0 vote200 views1 answer
Python proxy scraper
Python