Groupby where only

>>> df = pd.DataFrame({'A' : ['foo', 'bar', 'foo', 'bar',
...                           'foo', 'bar'],
...                    'B' : [1, 2, 3, 4, 5, 6],
...                    'C' : [2.0, 5., 8., 1., 2., 9.]})
>>> grouped = df.groupby('A')
>>> grouped.filter(lambda x: x['B'].mean() > 3.)
     A  B    C
1  bar  2  5.0
3  bar  4  1.0
5  bar  6  9.0

-1

Source: pandas.pydata.org

Similar codes

0 vote381 views2 answers
Update a package with pip in django
Python Django
1 vote331 views1 answer
Make solutions faster in python
Python
1 vote318 views2 answers
Python dict dot notation
Python
16 votes328 views6 answers
Joins in pandas
Python
1 vote299 views1 answer
Return json with flask
Python
0 vote325 views1 answer
Pandas read_csv multiple separator
Python
0 vote328 views1 answer
Minio python make an object
Python
23 votes290 views6 answers
How to check if a number is even or odd in python
Python
2 votes311 views1 answer
Replacing spaces in a string python
Python
0 vote321 views1 answer
Qtablewidget not editable python
Python