/Python/Python for loop start at index with enumerate

Python for loop start at index with enumerate

Python access index in for loop

for index, item in enumerate(items):
    print(index, item)

#if you want to start from 1 instead of 0
for count, item in enumerate(items, start=1):
    print(count, item)

Python for loop start at index with enumerate

items_list = ["python","enumerate","function","with","custom","start"]

custom_start = 1 # default_start = 0

for index,item in enumerate(items_list, start = custom_start):
     if index == 1:
         print("index starts at {custom_start} with a stored value of {list_value}".format(custom_start=index, list_value=item))
     else:
         print("index continues as {} with a value of {}".format(index,item))

Similar codes

0 vote216 views1 answer
There is no difference in R between a string scalar and a vector of strings
Python
0 vote265 views1 answer
Python path zsh mac
Python
2 votes266 views1 answer
Flask minimul app
Python
0 vote355 views1 answer
How to export schema in graphene django
Python Django
1 vote283 views1 answer
Sample based on column pandas
Python
0 vote277 views1 answer
Python concatenate tuple to string
Python
0 vote247 views1 answer
Python continue inner for loop
Python
13 votes270 views6 answers
Range() python
Python
2 votes314 views2 answers
Add hours to date time in python
Python
21 votes254 views1 answer
Plot x y graph python
Python