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Python check if list contains elements of another list

Check if a list contains an item from another list python

## checking any elment of list_B in list_A
list_A = [1, 2, 3, 4]

list_B = [2, 3, 6]

check = any(item in list_A for item in list_B)

print(check)
# True

Python check if list contains elements of another list

## checking all elements of list_B in list_A
list_A = [1, 2, 3, 4]
list_B = [2, 3]

check = all(item in list_A for item in list_B)

print(check)
# True

Python check list contains another list

>>> items = set([-1, 0, 1, 2])
>>> set([1, 2]).issubset(items)
True
>>> set([1, 3]).issubset(items)
False

Source: stackoverflow.com

Check if part of list is in another list python

'''    
    check if list1 contains any elements of list2
'''
result =  any(elem in list1  for elem in list2)
if result:
    print("Yes, list1 contains any elements of list2")    
else :
    print("No, list1 contains any elements of list2")

Check if a list contains any item from another list python

## using set
list_A = [1, 2, 3, 4]
list_B = [2, 3]

set_A = set(list_A)
set_B = set(list_B)

print(set_A.intersection(set_B))

# True if there is any element same
# False if there is no element same

How to check if a list contains elements in another list

##Taking examples of two python lists.

##Take examples of two lists.

list1 = [2,4,0,7,6]
list2 = [1,0,9,7,6]

##the statement for condition is.

check = any(element in list2 for element in list1)

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