/Python/Python code for diamond with gap between odd rows

Python code for diamond with gap between odd rows

//pgm for diamond pattern
print("Give the value of n(odd):")
n=int(input())        //input from the user is stored in n
x=n//2+1
//here two loops are combined into one by 'zip'
//loop for printing the first half diamond              
for i,j in zip(range(1,x+1),range(1,n+1,2)):   
    print(' '*(x-i)+'*'*(j))
//loop for printing the second half diamond(reverse half)
for i,j in zip(range(1,x+1),range(n-2,-1,-2)):
    print(' '*(i)+'*'*(j))

Source: geekstocode.com

Similar codes

25 votes120 views6 answers
Playsound python
Python
0 vote117 views1 answer
Create array with shape 0,2
Python
0 vote113 views1 answer
Python how to geather and spread using pandas
Python
1 vote152 views1 answer
Read files and write into another files python
Python
4 votes106 views2 answers
Split filename and extension python
Python
0 vote112 views1 answer
Pandas change frequency of datetimeindex
Python
0 vote118 views1 answer
Python get all items exept las from array
Python
7 votes93 views2 answers
Python print for loop one line
Python
1 vote64 views1 answer
Split dict into chunks python
Python
7 votes110 views6 answers
Python hello world
Python