/Python/Python code for diamond with gap between odd rows

Python code for diamond with gap between odd rows

//pgm for diamond pattern
print("Give the value of n(odd):")
n=int(input())        //input from the user is stored in n
x=n//2+1
//here two loops are combined into one by 'zip'
//loop for printing the first half diamond              
for i,j in zip(range(1,x+1),range(1,n+1,2)):   
    print(' '*(x-i)+'*'*(j))
//loop for printing the second half diamond(reverse half)
for i,j in zip(range(1,x+1),range(n-2,-1,-2)):
    print(' '*(i)+'*'*(j))

Source: geekstocode.com

Similar codes

6 votes322 views3 answers
Media url django
Python
-1 vote382 views1 answer
Cannot import name 'httpresponse' from 'django.http'
Python Django
0 vote374 views1 answer
Flask buildspec.yml
Python Flask
0 vote314 views1 answer
If else usage python
Python
0 vote324 views1 answer
Online python formatter and compiler
Python
0 vote355 views1 answer
Import re def check_time(text): pattern = ___ result = re.search(pattern, text) return result != None print(check_time("12:45pm")) # True print(check_time("9:59 AM")) # True print(check_time("6:60am")) # False print(chec
Python
0 vote322 views1 answer
Dataproc initialization_actions error
Python
13 votes328 views2 answers
Min int python
Python
0 vote359 views1 answer
Inline if statement python return
Python
3 votes298 views1 answer
Python 3.9 features
Python