Django admin actions

Django admin action

from django.contrib import admin
from myapp.models import Article

def make_published(modeladmin, request, queryset):
    queryset.update(status='p')
make_published.short_description = "Mark selected stories as published"

class ArticleAdmin(admin.ModelAdmin):
    list_display = ['title', 'status']
    ordering = ['title']
    actions = [make_published]

admin.site.register(Article, ArticleAdmin)

Source: grepper.com

Django admin action

# Add this code to admin.py
#example : Published Article
def make_published(modeladmin, request, queryset):
    queryset.update(status='p')
make_published.short_description = "Mark selected stories as published"

Source: grepper.com

Similar codes

0 vote175 views1 answer
Django model manager user
Python Django
0 vote220 views1 answer
Overriding update in serializer django
Python Django
0 vote239 views1 answer
Enumerate in django templte
Python Django
2 votes191 views1 answer
Django models distinct
Python Django
0 vote197 views1 answer
Django model make the field caseinsensitive
Python Django
0 vote188 views1 answer
Serializing nested objects drf,django restframework nested object serialization
Python Django
1 vote179 views1 answer
Django templateview
Python Django
0 vote183 views1 answer
Django-filter field name greater than
Python Django
2 votes191 views4 answers
Django login required
Python Django
0 vote131 views1 answer
HTTP Error 403: Forbidden django account signup email
Python Django