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Sum of array using recursion in python

Sum number in a list python using recursion

def listsum(numList):
   if len(numList) == 1:
        return numList[0]
   else:
        return numList[0] + listsum(numList[1:])

print(listsum([1,3,5,7,9]))

Source: grepper.com

Write a Python program of recursion list sum.

def sum_arr(arr,size):
   if (size == 0):
     return 0
   else:
     return arr[size-1] + sum_arr(arr,size-1)
n=int(input("Enter the number of elements for list:"))
a=[]
for i in range(0,n):
    element=int(input("Enter element:"))
    a.append(element)
print("The list is:")
print(a)
print("Sum of items in list:")
b=sum_arr(a,n)
print(b)

Source: sanfoundry.com

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