Leap year algorithm

def isLeapYear (year):
    if ((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0):
		true
    else:
    	false

Source: grepper.com

Leap year algorithm

if year % 4 == 0:
  if year % 100 == 0:
    if year % 400 == 0:
      print("leap year")
    else:
      print("not a leap year")
  else:
    print("leap year")
else:
  print("not a leap year")

Source: grepper.com

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