Alphabet position in python

Position in alphabet python

from string import ascii_lowercase
LETTERS = {letter: str(index) for index, letter in enumerate(ascii_lowercase, start=1)} 

def alphabet_position(text):
    text = text.lower()
    numbers = [LETTERS[character] for character in text if character in LETTERS]
    return ' '.join(numbers)

Source: grepper.com

Similar codes

1 vote352 views1 answer
Check if can convert to float python
Python
1 vote369 views1 answer
Reload all extensions discord.py
Python
53 votes358 views3 answers
How to find length of list python
Python
0 vote356 views1 answer
Spacy access vocabulary
Python
0 vote374 views1 answer
Create pandas df without column name toy dataset
Python
1 vote345 views1 answer
Tqdm command that works both in notebook and lab
Python
0 vote345 views1 answer
Ia
Python
-1 vote434 views1 answer
Install grepper for edge
Python
3 votes388 views2 answers
Numpy count the number of 1s in array
Python
0 vote347 views1 answer
Python csv delete all rows
Python