Alphabet position in python

Position in alphabet python

from string import ascii_lowercase
LETTERS = {letter: str(index) for index, letter in enumerate(ascii_lowercase, start=1)} 

def alphabet_position(text):
    text = text.lower()
    numbers = [LETTERS[character] for character in text if character in LETTERS]
    return ' '.join(numbers)

Source: grepper.com

Similar codes

17 votes372 views5 answers
Random python range
Python
6 votes395 views2 answers
Run python version from terminal
Python
29 votes509 views5 answers
Static dirs django
Python Django
0 vote318 views1 answer
Fibonacci series recursive python
Python
1 vote336 views2 answers
Convert timestamp to period pandas
Python
2 votes341 views1 answer
How to rewrite minute in datetime python
Python
15 votes385 views6 answers
Python filter
Python
0 vote324 views1 answer
TypeError: 'LazyCorpusLoader' object is not callable
Python
1 vote333 views1 answer
Valueerror need more than 2 values to unpack findcontours
Python
1 vote304 views1 answer
Access-Control-Allow-Origin django
Python