Alphabet position in python

Position in alphabet python

from string import ascii_lowercase
LETTERS = {letter: str(index) for index, letter in enumerate(ascii_lowercase, start=1)} 

def alphabet_position(text):
    text = text.lower()
    numbers = [LETTERS[character] for character in text if character in LETTERS]
    return ' '.join(numbers)

Source: grepper.com

Similar codes

0 vote307 views1 answer
Python set workdir
Python
0 vote309 views1 answer
Django active link
Python
0 vote302 views1 answer
Show all rows with nan for a column value pandas
Python
0 vote298 views1 answer
Django.com
Python
1 vote285 views1 answer
Add seconds to datetime python
Python
4 votes304 views5 answers
Random password generator
Python
0 vote334 views1 answer
Make value of two tables unique django
Python
1 vote322 views1 answer
Match python 3.10
Python
1 vote308 views1 answer
Pep full form
Python
2 votes329 views2 answers
Superscript python
Python