/PHP/PHP $argv echo

PHP $argv echo

PHP $argv echo

for ($i=0; $i < $argc; $i++) {
    echo $argv[$i] . "\n";
}

0

Source: zetcode.com

PHP $argv echo with number of words

<?php echo "There are $argc arguments\n";for ($i=0; $i < $argc; $i++) {
    echo $argv[$i] . "\n";
}

0

Source: zetcode.com

Similar codes

6 votes174 views6 answers
Install php 7.3 ubuntu
PHP
6 votes162 views1 answer
A2dismod php 8.0
PHP
0 vote166 views1 answer
How to update a table based on three columns laravel
PHP
0 vote163 views1 answer
How to print image just on side where upload php
PHP
3 votes145 views1 answer
Wordpress base theme child url
PHP
4 votes188 views2 answers
Laravel session forget
PHP Laravel
0 vote152 views1 answer
Back()->with('message','Successfully Updated the Password'); larvel
PHP
1 vote180 views4 answers
Php boolean to string
PHP
0 vote173 views1 answer
Php pdo set charset
PHP
0 vote152 views1 answer
Return json in middleware laravel
PHP

Share