/Shell/Bash/Swapping of two numbers without using third variable in shell script

Swapping of two numbers without using third variable in shell script

#!/bin/bash
echo "enter first number"
read a
echo "enter second number"
read b
echo "a before swapping is $a and b is $b"
#swapping
a=$((a+b))
b=$((a - b))
a=$((a-b))
echo "a after swapping is  $a and b is $b"

Source: technicalworldforyou.blogspot.com

Similar codes

0 vote386 views1 answer
How to abort a rebase
Shell/Bash
0 vote349 views1 answer
Git test ssh
Shell/Bash
0 vote352 views1 answer
Bash: fork: Cannot allocate memory
Shell/Bash
0 vote348 views3 answers
Git remote add ssh
Shell/Bash
1 vote333 views1 answer
Database metasploit kali linux
Shell/Bash
-1 vote380 views2 answers
Putty for ubuntu
Shell/Bash
3 votes358 views3 answers
How to shutdown linux from terminal immediately
Shell/Bash
0 vote337 views1 answer
Bashub
Shell/Bash
1 vote381 views4 answers
Error: command 'x86_64-linux-gnu-gcc' failed with exit status 1
Shell/Bash
1 vote436 views1 answer
Cron can't change wallpaper ubuntu
Shell/Bash