/Shell/Bash/Swapping of two numbers without using third variable in shell script

Swapping of two numbers without using third variable in shell script

#!/bin/bash
echo "enter first number"
read a
echo "enter second number"
read b
echo "a before swapping is $a and b is $b"
#swapping
a=$((a+b))
b=$((a - b))
a=$((a-b))
echo "a after swapping is  $a and b is $b"

Source: technicalworldforyou.blogspot.com

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