/Shell/Bash/Swapping of two numbers without using third variable in shell script

Swapping of two numbers without using third variable in shell script

#!/bin/bash
echo "enter first number"
read a
echo "enter second number"
read b
echo "a before swapping is $a and b is $b"
#swapping
a=$((a+b))
b=$((a - b))
a=$((a-b))
echo "a after swapping is  $a and b is $b"

Source: technicalworldforyou.blogspot.com

Similar codes

0 vote226 views1 answer
Create folder putty linux
Shell/Bash
0 vote215 views1 answer
Git download a new branch
Shell/Bash
0 vote230 views1 answer
Get old commit based on active users
Shell/Bash
-1 vote226 views1 answer
Next js tailwind
Shell/Bash
0 vote237 views1 answer
Git reset in gitlab
Shell/Bash
0 vote236 views1 answer
Pip install cookiecutter
Shell/Bash
21 votes254 views4 answers
Remove a package ubuntu
Shell/Bash
-2 votes232 views1 answer
Tomcat install on linux
Shell/Bash
1 vote216 views1 answer
Npm mysql
Shell/Bash
0 vote222 views1 answer
Install raylib osx
Shell/Bash