/Shell/Bash/Swapping of two numbers without using third variable in shell script

Swapping of two numbers without using third variable in shell script

#!/bin/bash
echo "enter first number"
read a
echo "enter second number"
read b
echo "a before swapping is $a and b is $b"
#swapping
a=$((a+b))
b=$((a - b))
a=$((a-b))
echo "a after swapping is  $a and b is $b"

Source: technicalworldforyou.blogspot.com

Similar codes

1 vote296 views1 answer
Vim comment out mutiple lines
Shell/Bash
16 votes299 views1 answer
Angular install firebase tools
Shell/Bash
0 vote339 views1 answer
Mac end process shortcut
Shell/Bash
0 vote305 views1 answer
Brew services start [email protected]
Shell/Bash
1 vote337 views1 answer
Scp permission denied (publickey) but ssh works
Shell/Bash
0 vote330 views1 answer
Powershell list usb devices
Shell/Bash
0 vote319 views1 answer
Laptop slow performance linux
Shell/Bash
0 vote307 views1 answer
Install virtualenv conda
Shell/Bash
0 vote372 views1 answer
Ubuntu terminal search command
Shell/Bash
1 vote317 views2 answers
Debian docker
Shell/Bash