/Python/Django create view filter options

Django create view filter options

class FolderForm(forms.ModelForm):
    class Meta:
       model = Folder
       fields = ['name', 'parent']

    def __init__(self, *args, **kwargs):
       user = kwargs.pop('user')
       super(FolderForm, self).__init__(*args, **kwargs)
       self.fields['parent'].queryset = Folder.objects.filter(user=user)

Source: stackoverflow.com

Django create view filter options

class FolderCreate(CreateView):
    template_name = 'Form/folder_create.html'
    form_class = FolderForm

    def get_form_kwargs(self):
        kwargs = super(FolderCreate, self).get_form_kwargs()
        kwargs['user'] = self.request.user
        return kwargs

Source: stackoverflow.com

Similar codes

0 vote304 views1 answer
Get list of users django
Python
0 vote298 views1 answer
Indice d'un element dans une liste python
Python
0 vote342 views1 answer
How to add picture in phyton
Python
0 vote321 views1 answer
Matplotlib include first number in plotter
Python
3 votes327 views1 answer
The authorization mechanism you have provided is not supported. Please use AWS4-HMAC-SHA256
Python
1 vote319 views1 answer
Python csv update row
Python
0 vote281 views1 answer
Train_test_split without shuffle
Python
0 vote297 views1 answer
Python tkinter get image size
Python
0 vote304 views1 answer
Python if index in list exists
Python
1 vote296 views6 answers
How to hello world in python
Python