/Python/Django create view filter options

Django create view filter options

class FolderForm(forms.ModelForm):
    class Meta:
       model = Folder
       fields = ['name', 'parent']

    def __init__(self, *args, **kwargs):
       user = kwargs.pop('user')
       super(FolderForm, self).__init__(*args, **kwargs)
       self.fields['parent'].queryset = Folder.objects.filter(user=user)

Source: stackoverflow.com

Django create view filter options

class FolderCreate(CreateView):
    template_name = 'Form/folder_create.html'
    form_class = FolderForm

    def get_form_kwargs(self):
        kwargs = super(FolderCreate, self).get_form_kwargs()
        kwargs['user'] = self.request.user
        return kwargs

Source: stackoverflow.com

Similar codes

10 votes260 views2 answers
Create dict from json file python
Python
36 votes278 views6 answers
Move files in python
Python
0 vote292 views2 answers
Loop through file python
Python
0 vote273 views1 answer
Python tkinter interface exoskeleton
Python
28 votes402 views3 answers
Django abstractuser
Python Django
1 vote261 views1 answer
Python convert base
Python
9 votes275 views4 answers
For if else one line python
Python
0 vote254 views2 answers
Python simple project
Python
7 votes270 views1 answer
Python for loop with array
Python
0 vote252 views1 answer
Python remove middle of string
Python