Pe039

def number_of_solution(p):
    num = 0
    for a in range(1,p//3):
        if (p**2-2*p*a)%(2*p-2*a) == 0:
            num += 1
    return num

def main(n=1000):
    d = {p:number_of_solution(p) for p in range(2,n+1,2)}
    ans = max(d,key=d.get)
    return ans

Source: pe.metaquant.org

Similar codes

0 vote245 views1 answer
Fibonacci program in python
Python
0 vote240 views1 answer
Replit python keep discord bot online
Python
0 vote222 views1 answer
Make a function that accepts any nuber of arguments python
Python
0 vote251 views1 answer
Displace items in array python
Python
1 vote254 views1 answer
Django set default value for model not form
Python Django
0 vote221 views1 answer
How to check if column has na python
Python
2 votes250 views1 answer
Python print dictionary line by line
Python
14 votes238 views6 answers
Join tables pandas
Python
0 vote220 views1 answer
How to make minecraft using python
Python
2 votes250 views3 answers
How to use readline in python
Python