Nested dictionary Python

IDs = ['emp1','emp2','emp3']

EmpInfo = [{'name': 'Bob', 'job': 'Mgr'},
           {'name': 'Kim', 'job': 'Dev'},
           {'name': 'Sam', 'job': 'Dev'}]

D = dict(zip(IDs, EmpInfo))

print(D)
# Prints {'emp1': {'name': 'Bob', 'job': 'Mgr'},
#         'emp2': {'name': 'Kim', 'job': 'Dev'},
#         'emp3': {'name': 'Sam', 'job': 'Dev'}}

Source: learnbyexample.org

Python nested object to dict

def my_dict(obj):
    if not  hasattr(obj,"__dict__"):
        return obj
    result = {}
    for key, val in obj.__dict__.items():
        if key.startswith("_"):
            continue
        element = []
        if isinstance(val, list):
            for item in val:
                element.append(my_dict(item))
        else:
            element = my_dict(val)
        result[key] = element
    return result

Source: stackoverflow.com

Make nested dict from two dict

data = [
    [14, 77766, [2, 2]],
    [15, 77766, [1, 2]],
    [70, 88866, [1, 5]],
    [71, 88866, [2, 5]],
    [72, 88866, [5, 5]],
    [73, 88866, [4, 5]],
    [74, 88866, [3, 5]],
    [79, 99966, [1, 2]],
    [80, 99966, [2, 2]],
]

c = {}
for key, id_, (value, _) in data:
    c.setdefault(id_, {})[key] = value
print(c)

-1

Source: stackoverflow.com

Similar codes

0 vote372 views1 answer
Install matplotlib.pyplot mac python 3
Python
0 vote331 views2 answers
Python top label plot
Python
1 vote351 views1 answer
Python background function
Python
0 vote353 views1 answer
Inspect last 5 rows of dataframe
Python
0 vote344 views1 answer
Spark.read.load
Python
1 vote390 views2 answers
Flask bootstrap
Python Flask
0 vote342 views1 answer
Count different values in list python
Python
3 votes326 views1 answer
AttributeError: module 'librosa' has no attribute 'display' site:stackoverflow.com
Python
12 votes341 views4 answers
How to install Numpy
Python
0 vote366 views1 answer
How to view back of list in python
Python