/Python/Python find matching string regardless of case

Python find matching string regardless of case

# credit to the Stack Overflow users in the source lin
# with regex
import re
if re.search('mandy', 'Mandy Pande', re.IGNORECASE):
   # do your stuff here
   # Note:
   # results = re.search('mandy', 'Mandy Pande', re.IGNORECASE)
   # results.group(0) is the string that matched ('Mandy')

# without regex
string1 = "hi"
string2 = "HI"
if string1.lower() == string2.lower():
    print("Equals!")
else:
    print("Different!")

Source: stackoverflow.com

Similar codes

1 vote318 views1 answer
Running setup.py bdist_wheel for opencv-python: still running...
Python
0 vote272 views1 answer
Change value in excel in python
Python
2 votes265 views2 answers
Python ping api
Python
0 vote292 views1 answer
Bs4 python delete element
Python
0 vote278 views1 answer
Backend not found Request Method: GET Request URL: http://127.0.0.1:8000/oauth/login/google-oauth2/ Raised by: social_django.views.au
Python
1 vote331 views1 answer
Module "django.contrib.auth.hashers" does not define a "BcryptPasswordHasher" attribute/class
Python Django
42 votes286 views4 answers
Import datetime
Python
1 vote264 views1 answer
Get_or_create in django
Python
1 vote309 views2 answers
Ast python
Python
8 votes311 views3 answers
Float python precision
Python