/Python/Python find matching string regardless of case

Python find matching string regardless of case

# credit to the Stack Overflow users in the source lin
# with regex
import re
if re.search('mandy', 'Mandy Pande', re.IGNORECASE):
   # do your stuff here
   # Note:
   # results = re.search('mandy', 'Mandy Pande', re.IGNORECASE)
   # results.group(0) is the string that matched ('Mandy')

# without regex
string1 = "hi"
string2 = "HI"
if string1.lower() == string2.lower():
    print("Equals!")
else:
    print("Different!")

Source: stackoverflow.com

Similar codes

1 vote336 views1 answer
Timedelta to float
Python
0 vote315 views1 answer
Python format method align center
Python
0 vote368 views1 answer
Add to middle of string python
Python
1 vote340 views1 answer
Python ssh library
Python
0 vote312 views2 answers
Call shell script from python
Python
0 vote367 views1 answer
Pyplot savefig
Python
0 vote326 views2 answers
Pandas series filter by index
Python
0 vote391 views1 answer
Github blxo
Python
0 vote331 views1 answer
How to print stdout while processing the execution in python
Python
0 vote313 views1 answer
ImportError: /home/user/.local/lib/python3.8/site-packages/pytorch3d/_C.cpython-38-x86_64-linux-gnu.so: undefined symbol: _ZN2at5zerosEN3c108ArrayRefIlEENS0_13TensorOptionsE
Python