/Python/Python find matching string regardless of case

Python find matching string regardless of case

# credit to the Stack Overflow users in the source lin
# with regex
import re
if re.search('mandy', 'Mandy Pande', re.IGNORECASE):
   # do your stuff here
   # Note:
   # results = re.search('mandy', 'Mandy Pande', re.IGNORECASE)
   # results.group(0) is the string that matched ('Mandy')

# without regex
string1 = "hi"
string2 = "HI"
if string1.lower() == string2.lower():
    print("Equals!")
else:
    print("Different!")

Source: stackoverflow.com

Similar codes

2 votes248 views2 answers
Or in django query
Python Django
0 vote264 views1 answer
Pandas isin another dataframe column
Python
1 vote192 views1 answer
In array number of dictionaries python
Python
1 vote221 views1 answer
From time import sleep, time
Python
0 vote228 views1 answer
Odoo 12 compute documentation
Python
2 votes220 views1 answer
Shutdown/restart/hibernate/logoff windows with python
Python
2 votes219 views2 answers
Python infinite l00p
Python
1 vote245 views1 answer
Date difference in minutes in Python
Python
1 vote270 views1 answer
No module named base45 windows
Python
5 votes239 views1 answer
Selenium webdriver imports
Python