/Python/Python find matching string regardless of case

Python find matching string regardless of case

# credit to the Stack Overflow users in the source lin
# with regex
import re
if re.search('mandy', 'Mandy Pande', re.IGNORECASE):
   # do your stuff here
   # Note:
   # results = re.search('mandy', 'Mandy Pande', re.IGNORECASE)
   # results.group(0) is the string that matched ('Mandy')

# without regex
string1 = "hi"
string2 = "HI"
if string1.lower() == string2.lower():
    print("Equals!")
else:
    print("Different!")

Source: stackoverflow.com

Similar codes

0 vote301 views1 answer
Convert string to object in python
Python
-1 vote316 views3 answers
Transpose of a matrix in python numpy
Python
0 vote282 views1 answer
Count numbers that add up to 10 in python
Python
3 votes317 views6 answers
2+2
Python
0 vote300 views1 answer
Python pandas table save
Python
0 vote327 views1 answer
Confusion matrix seaborn
Python
0 vote326 views1 answer
Find maximum value by if else python
Python
8 votes347 views2 answers
Python count files directory
Python
25 votes288 views2 answers
Python colored text in console
Python
0 vote324 views1 answer
Pandas add prefix to column names
Python