/Python/Python find matching string regardless of case

Python find matching string regardless of case

# credit to the Stack Overflow users in the source lin
# with regex
import re
if re.search('mandy', 'Mandy Pande', re.IGNORECASE):
   # do your stuff here
   # Note:
   # results = re.search('mandy', 'Mandy Pande', re.IGNORECASE)
   # results.group(0) is the string that matched ('Mandy')

# without regex
string1 = "hi"
string2 = "HI"
if string1.lower() == string2.lower():
    print("Equals!")
else:
    print("Different!")

Source: stackoverflow.com

Similar codes

6 votes218 views1 answer
All tkinter events
Python
0 vote272 views1 answer
India states django choices
Python
0 vote246 views1 answer
Flask - store object directly in a session [duplicate]
Python
0 vote222 views1 answer
How to load multiple list of dictionary values which is stored in python file and load into another python file in python over loop
Python
11 votes236 views4 answers
Flask debug
Python
0 vote251 views1 answer
Visual Studio Code doesn't stop on Python breakpoint debug
Python
81 votes247 views6 answers
Loop in python
Python
-1 vote242 views1 answer
Randoomforest sklearn
Python
0 vote236 views1 answer
Saving a copy of rcParams settings.
Python
6 votes252 views3 answers
How to remove all zeros from a list in python
Python