/Shell/Bash/Dos assign carriage return to variable

Dos assign carriage return to variable

set myLinefeed=^<LF1>
<LF2>
<LF3>

Source: stackoverflow.com

Dos assign carriage return to variable

setlocal EnableDelayedExpansion
set LF=^


rem TWO empty lines are required
echo This text!LF!uses two lines

Source: stackoverflow.com

Dos assign carriage return to variable

(SET LF=^
%=this line is empty=%
)

Source: stackoverflow.com

Dos assign carriage return to variable

set LF=^


rem TWO empty lines are required
echo This text^%LF%%LF%uses two lines
echo This also^

uses two lines

Source: stackoverflow.com

Dos assign carriage return to variable

if "!LF!" NEQ "!LF:~0,1!" echo Error "Linefeed definition is defect, probably multiple invisble whitespaces at the line end in the definition of LF"

FOR /F "delims=" %%n in ("!LF!") do (
  echo Error "Linefeed definition is defect, probably invisble whitespaces at the line end in the definition of LF"
)

Source: stackoverflow.com

Similar codes

0 vote232 views1 answer
Awk pdb format
Shell/Bash
0 vote244 views1 answer
Burp suite kali linux
Shell/Bash
5 votes241 views1 answer
Ports unavailable 9000 windows
Shell/Bash
0 vote251 views1 answer
Gradle init scala
Shell/Bash
0 vote249 views1 answer
Git fetch rebase
Shell/Bash
0 vote251 views1 answer
How to unlock minimize button on gnome
Shell/Bash
0 vote233 views1 answer
Clamscan version command
Shell/Bash
0 vote244 views1 answer
Jq print array
Shell/Bash
2 votes233 views1 answer
Env file in firebase
Shell/Bash
3 votes257 views3 answers
Ssh get key
Shell/Bash