Python try except

How to print error in try except python

try:
  # some code
except Exception as e:
	print("ERROR : "+str(e))

Except as Exception:

>>> def catch():
...     try:
...         asd()
...     except Exception as e:
...         print e.message, e.args
... 
>>> catch()
global name 'asd' is not defined ("global name 'asd' is not defined",)

Source: stackoverflow.com

Python try except

import sys

try:
    f = open('myfile.txt')
    s = f.readline()
    i = int(s.strip())
except OSError as err:
    print("OS error: {0}".format(err))
except ValueError:
    print("Could not convert data to an integer.")
except:
    print("Unexpected error:", sys.exc_info()[0])
    raise

Print type of exception python

try:
    someFunction()
except Exception as ex:
    template = "An exception of type {0} occurred. Arguments:\n{1!r}"
    message = template.format(type(ex).__name__, ex.args)
    print (message)

Source: stackoverflow.com

Python try except

try:
  val = 1/0 
except Exception as e:
  raise Exception('ZeroDivisionError')

Python try except

try:
  print("I will try to print this line of code")
except Exception as e:
  print(f"Error message: {}")

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