/Python/Py - count if a word is present in a column

Py - count if a word is present in a column

words = 'one two three'.split()

df.assign(counts=df.texts.str.count('|'.join(words)))

        texts  counts
0  throne one       2
1     bar one       1
2     foo two       1
3   bar three       1
4     foo two       1
5     bar two       1
6     foo one       1
7   foo three       1
8   one three       2

Source: stackoverflow.com

Similar codes

31 votes261 views6 answers
Try except python
Python
0 vote256 views1 answer
How to repeat if statement in python
Python
125 votes286 views6 answers
How to take input from user in python
Python
0 vote274 views1 answer
Import CreateAPIView django
Python
14 votes272 views5 answers
Server in python
Python
0 vote257 views1 answer
Pyhton apend to list
Python
0 vote291 views2 answers
Loop through file python
Python
77 votes259 views6 answers
Reverse a string python
Python
1 vote276 views2 answers
Tensor vs numpy array
Python
0 vote260 views1 answer
Copyfile pyhon
Python