/Python/Py - count if a word is present in a column

Py - count if a word is present in a column

words = 'one two three'.split()

df.assign(counts=df.texts.str.count('|'.join(words)))

        texts  counts
0  throne one       2
1     bar one       1
2     foo two       1
3   bar three       1
4     foo two       1
5     bar two       1
6     foo one       1
7   foo three       1
8   one three       2

Source: stackoverflow.com

Similar codes

78 votes169 views6 answers
Python sort dict by value
Python
0 vote155 views1 answer
Python division no remainder
Python
0 vote172 views1 answer
Sublime python build system
Python
1 vote161 views1 answer
Reject invalid input using a loop in python
Python
10 votes162 views1 answer
How to get specific row in pandas
Python
0 vote181 views1 answer
Python difference between filter and map
Python
0 vote214 views1 answer
Python make 1d array from n-d array
Python
1 vote161 views1 answer
Python try except continue loop
Python
3 votes157 views2 answers
Python writelines newline
Python
0 vote166 views1 answer
Python tkinter colored line
Python