/Python/Pandas apply function to each row lambda

Pandas apply function to each row lambda

def EOQ(D,p,ck,ch):
    Q = math.sqrt((2*D*ck)/(ch*p))
    return Q
ch=0.2
ck=5
df['Q'] = df.apply(lambda row: EOQ(row['D'], row['p'], ck, ch), axis=1)
df

Source: stackoverflow.com

Similar codes

17 votes315 views2 answers
Make password python
Python
0 vote323 views2 answers
How to find unique sublist in list in python
Python
0 vote302 views1 answer
How to create a numpy array with constant value
Python
0 vote341 views1 answer
Epoch to datetime utc python
Python
0 vote327 views1 answer
Django file upload this field is required
Python Django
8 votes329 views5 answers
Retrieve row by index pandas
Python
0 vote290 views1 answer
Sns.lineplot
Python
0 vote308 views1 answer
Python create unreadable save file
Python
71 votes325 views6 answers
Alphabet list python
Python
4 votes311 views3 answers
Pandas df by row index
Python