Php regex markdown link

$text = 'Link to [Google](https://www.google.com/)';
echo preg_replace('/\[(.*?)\]\s*\(((?:http:\/\/|https:\/\/)(?:.+))\)/', '<a href="$2">$1</a>', $text);
// Outputs: Link to <a href="https://www.google.com/">Google</a>

Source: stackoverflow.com

Similar codes

0 vote238 views1 answer
How to use union and intersection in laravel query
PHP
5 votes276 views4 answers
Laravel remove foreign key
PHP Laravel
0 vote233 views1 answer
Wordpress get page number
PHP
48 votes346 views6 answers
Laravel joins
PHP Laravel
2 votes252 views2 answers
Validate password laravel
PHP Laravel
0 vote250 views1 answer
Php enc
PHP
0 vote306 views3 answers
Laravel Eloquent sum of multiplied columns
PHP Laravel
0 vote296 views1 answer
Les étape d'integration du templates adminlte de Laravel pour application
PHP Laravel
0 vote259 views2 answers
Wp colibri delete footer
PHP
5 votes240 views4 answers
Insert data using seeder in laravel
PHP