Numpy.where() for substring

foo = 'aa'
bar = np.array(['aaa', 'aab', 'aca'])
out = [i for i, v in enumerate(bar) if foo in v]
# out = [0, 1]

bar = ['aca', 'bba', 'baa', 'aaf', 'ccc']
out = [i for i, v in enumerate(bar) if foo in v]
# out = [2, 3]

Source: stackoverflow.com

Similar codes

1 vote287 views1 answer
Python hasattribute
Python
28 votes274 views2 answers
Making your own range function with step in python
Python
0 vote327 views1 answer
One2many add tuple
Python
2 votes299 views3 answers
How to set indian timezone in django
Python
1 vote297 views1 answer
How to find magnitude of complex number in python
Python
0 vote320 views1 answer
Inline if statement python return
Python
0 vote260 views1 answer
Count occurrences of one variable grouped by another python
Python
0 vote323 views1 answer
How to use with statementin python 2.4
Python
0 vote298 views1 answer
Gun in python turtle
Python
0 vote292 views1 answer
Default orange and blue matplotlib
Python