/Java/Count occurrences in seven integers using java single dimension arrays

Count occurrences in seven integers using java single dimension arrays

public static int count(int[] arr, int num) {
        int count = 0;
        for(int i = 0; i < arr.length; ++i) {   // go through all elements in array
            if(arr[i] == num) { // if num is found, increase count
                count++;    // increment count
            }
        }
        return count;   // return the count of number of occurrences of num in array
    }

    public static boolean checkIfElementAlreadyExists(int[] arr, int index) {
        for(int i = 0; i < index; ++i) {    // go through all elements in array
            if(arr[i] == arr[index]) {  // if item in index already exists in the array
                return true;    // then return true
            }
        }
        return false;   // if element at index does not previously occur, then return false
    }

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int[] arr = new int[7];
        System.out.print("Enter seven numbers: ");
        for(int i = 0; i < arr.length; ++i) {
            arr[i] = in.nextInt();  // read 7 numbers into array
        }
        for(int i = 0; i < arr.length; ++i) {   // go through all elements
            if(!checkIfElementAlreadyExists(arr, i)) {  // if this element did not already appear before in the array
                System.out.printf("Number %d occurs %d times.\n", arr[i], count(arr, arr[i]));  // then print the number and the number of time it occurs in the array
            }
        }
    }
}

Source: chegg.com

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