Check status code urllib

import urllib.request, urllib.error

url = 'http://www.google.com/asdfsf'
try:
    conn = urllib.request.urlopen(url)
except urllib.error.HTTPError as e:
    # Return code error (e.g. 404, 501, ...)
    # ...
    print('HTTPError: {}'.format(e.code))
except urllib.error.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
    print('URLError: {}'.format(e.reason))
else:
    # 200
    # ...
    print('good')

Source: stackoverflow.com

Check status code urllib

import urllib2

req = urllib2.Request('http://www.python.org/fish.html')
try:
    resp = urllib2.urlopen(req)
except urllib2.HTTPError as e:
    if e.code == 404:
        # do something...
    else:
        # ...
except urllib2.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
else:
    # 200
    body = resp.read()

Source: stackoverflow.com

Similar codes

1 vote263 views1 answer
Python namespace packages
Python
16 votes228 views1 answer
Add to index python
Python
2 votes271 views2 answers
Array of random integers python
Python
0 vote270 views1 answer
How to get a rectangular grid out of two given one-dimensional arrays
Python
2 votes251 views1 answer
Pychamrfind and replace
Python
0 vote284 views1 answer
Python while loop
Python
29 votes295 views6 answers
Update all pip packages
Python
0 vote280 views1 answer
Python hide print output
Python
0 vote318 views1 answer
How to config django templates with pathlib
Python Django
0 vote274 views1 answer
Cast image to float32
Python