Check status code urllib

import urllib.request, urllib.error

url = 'http://www.google.com/asdfsf'
try:
    conn = urllib.request.urlopen(url)
except urllib.error.HTTPError as e:
    # Return code error (e.g. 404, 501, ...)
    # ...
    print('HTTPError: {}'.format(e.code))
except urllib.error.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
    print('URLError: {}'.format(e.reason))
else:
    # 200
    # ...
    print('good')

Source: stackoverflow.com

Check status code urllib

import urllib2

req = urllib2.Request('http://www.python.org/fish.html')
try:
    resp = urllib2.urlopen(req)
except urllib2.HTTPError as e:
    if e.code == 404:
        # do something...
    else:
        # ...
except urllib2.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
else:
    # 200
    body = resp.read()

Source: stackoverflow.com

Similar codes

0 vote220 views1 answer
Setting a conditional variable in python. Using an if else statement in python.
Python
1 vote246 views1 answer
R2 score sklearn
Python
-4 votes213 views4 answers
Python 3.2 release date
Python
0 vote257 views1 answer
Check if a date is reached django
Python Django
0 vote274 views2 answers
Fetching data from multiple tables using related name in django
Python
0 vote224 views1 answer
ModuleNotFoundError: No module named 'textract'
Python
0 vote250 views1 answer
Plotly vertical bar chart
Python
73 votes320 views5 answers
Python forEach list
Python
8 votes231 views6 answers
Declare variable in python
Python
0 vote222 views1 answer
Python path zsh mac
Python