Classement rang mysql 7

Bill    32  M   4
Bob     25  M   2
Jack    30  M   3
Nick    22  M   1
Steve   36  M   5
Anne    25  F   3
Jane    20  F   2
Kathy   18  F   1

Source: qastack.fr

Classement rang mysql 7

SELECT    a.first_name,
      a.age,
      a.gender,
        count(b.age)+1 as rank
FROM  person a left join person b on a.age>b.age and a.gender=b.gender 
group by  a.first_name,
      a.age,
      a.gender

Source: qastack.fr

Classement rang mysql 7

CREATE TABLE person (id int, first_name varchar(20), age int, gender char(1));

INSERT INTO person VALUES (1, 'Bob', 25, 'M');
INSERT INTO person VALUES (2, 'Jane', 20, 'F');
INSERT INTO person VALUES (3, 'Jack', 30, 'M');
INSERT INTO person VALUES (4, 'Bill', 32, 'M');
INSERT INTO person VALUES (5, 'Nick', 22, 'M');
INSERT INTO person VALUES (6, 'Kathy', 18, 'F');
INSERT INTO person VALUES (7, 'Steve', 36, 'M');
INSERT INTO person VALUES (8, 'Anne', 25, 'F');

Source: qastack.fr

Similar codes

40 votes208 views4 answers
PostgreSQL add column
SQL
23 votes183 views2 answers
Query to delete a database in mysql
SQL
2 votes177 views4 answers
2nd highest salary in mysql
SQL
0 vote184 views1 answer
Mysql date format unix timestamp
SQL
7 votes178 views5 answers
Oracle alter table
SQL
0 vote180 views1 answer
Sqlalchemy empty table
SQL
3 votes162 views1 answer
Oracle limit user tablespace
SQL
0 vote165 views1 answer
Check mysql password with docker container magento 2
SQL
5 votes172 views1 answer
Sort order on two columns sql
SQL
0 vote179 views1 answer
Sqlalchemy query join many to many
SQL