Classement rang mysql 7

Bill    32  M   4
Bob     25  M   2
Jack    30  M   3
Nick    22  M   1
Steve   36  M   5
Anne    25  F   3
Jane    20  F   2
Kathy   18  F   1

Source: qastack.fr

Classement rang mysql 7

SELECT    a.first_name,
      a.age,
      a.gender,
        count(b.age)+1 as rank
FROM  person a left join person b on a.age>b.age and a.gender=b.gender 
group by  a.first_name,
      a.age,
      a.gender

Source: qastack.fr

Classement rang mysql 7

CREATE TABLE person (id int, first_name varchar(20), age int, gender char(1));

INSERT INTO person VALUES (1, 'Bob', 25, 'M');
INSERT INTO person VALUES (2, 'Jane', 20, 'F');
INSERT INTO person VALUES (3, 'Jack', 30, 'M');
INSERT INTO person VALUES (4, 'Bill', 32, 'M');
INSERT INTO person VALUES (5, 'Nick', 22, 'M');
INSERT INTO person VALUES (6, 'Kathy', 18, 'F');
INSERT INTO person VALUES (7, 'Steve', 36, 'M');
INSERT INTO person VALUES (8, 'Anne', 25, 'F');

Source: qastack.fr

Similar codes

0 vote338 views1 answer
Insert or update sql query
SQL
9 votes324 views2 answers
Sql limit order by
SQL
0 vote387 views1 answer
Connect google bigquery connect using sqirrel
SQL
1 vote326 views2 answers
Sqlalchemy postgres timestamp with timezone
SQL
0 vote362 views1 answer
Mysql order by rand limit 1 really slow
SQL
1 vote333 views1 answer
Found option without preceding group in config file: /etc/mysql/mariadb.conf.d/50-server.cnf at line: 1
SQL
0 vote423 views1 answer
Compare strings lexicographically in sql
SQL
0 vote322 views1 answer
Data structures in sql
SQL
1 vote344 views2 answers
Mysql switch case
SQL
3 votes312 views1 answer
Oracle function
SQL