Classement rang mysql 7

Bill    32  M   4
Bob     25  M   2
Jack    30  M   3
Nick    22  M   1
Steve   36  M   5
Anne    25  F   3
Jane    20  F   2
Kathy   18  F   1

Source: qastack.fr

Classement rang mysql 7

SELECT    a.first_name,
      a.age,
      a.gender,
        count(b.age)+1 as rank
FROM  person a left join person b on a.age>b.age and a.gender=b.gender 
group by  a.first_name,
      a.age,
      a.gender

Source: qastack.fr

Classement rang mysql 7

CREATE TABLE person (id int, first_name varchar(20), age int, gender char(1));

INSERT INTO person VALUES (1, 'Bob', 25, 'M');
INSERT INTO person VALUES (2, 'Jane', 20, 'F');
INSERT INTO person VALUES (3, 'Jack', 30, 'M');
INSERT INTO person VALUES (4, 'Bill', 32, 'M');
INSERT INTO person VALUES (5, 'Nick', 22, 'M');
INSERT INTO person VALUES (6, 'Kathy', 18, 'F');
INSERT INTO person VALUES (7, 'Steve', 36, 'M');
INSERT INTO person VALUES (8, 'Anne', 25, 'F');

Source: qastack.fr

Similar codes

6 votes334 views3 answers
Update with inner join postgres
SQL
5 votes291 views1 answer
Mongodb vs
SQL
0 vote311 views1 answer
How much table store postgres
SQL
1 vote323 views1 answer
How to open closed port mysql in ubuntu
SQL
0 vote312 views1 answer
SQL Error 1040 : Too many connections
SQL
0 vote312 views1 answer
Json_remove mysql
SQL
1 vote332 views1 answer
Cannot drop database because it is currently in use
SQL
16 votes336 views1 answer
Mysql smallint range
SQL
1 vote327 views1 answer
Sysdate in sql
SQL
2 votes310 views2 answers
Postgres set user as superuser
SQL