Python try except print error

How to print error in try except python

try:
  # some code
except Exception as e:
	print("ERROR : "+str(e))

Python exception

try:
  # code block
except ValueError as ve:
  print(ve)

Except as Exception:

>>> def catch():
...     try:
...         asd()
...     except Exception as e:
...         print e.message, e.args
... 
>>> catch()
global name 'asd' is not defined ("global name 'asd' is not defined",)

Source: stackoverflow.com

Catch error data with except python

import sys
try:
	S = 1/0 #Create Error
except: # catch *all* exceptions
    e = sys.exc_info()
    print(e) # (Exception Type, Exception Value, TraceBack)

############
#    OR    #
############
try:
	S = 1/0
except ZeroDivisionError as e:
    print(e) # ZeroDivisionError('division by zero')

Python file open try except error

def FileCheck(fn):
    try:
      open(fn, "r")
      return 1
    except IOError:
      print "Error: File does not appear to exist."
      return 0

result = FileCheck("testfile")
print result

Source: stackoverflow.com

Python try except print error

   1 (x,y) = (5,0)
   2 try:
   3   z = x/y
   4 except ZeroDivisionError as e:
   5   z = e # representation: "<exceptions.ZeroDivisionError instance at 0x817426c>"
   6 print z # output: "integer division or modulo by zero"

-1

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