Python pattern match

Re python3

import re
>>> m = re.search('(?<=abc)def', 'abcdef')
>>> m.group(0)
'def'

Source: docs.python.org

Python pattern match

import re
pattern = re.compile('[a-zA-Z ]+')		# a...z A...Z and space allowed
message = "Weather is nice"
if pattern.match(message).group() == message:
    print("match")
else:
    print("no match")

Re.match python

import re
xx = "guru99,education11 is fun"
r1 = re.findall(r"^\w+",xx)
print(r1)

Source: guru99.com

Similar codes

1 vote289 views1 answer
Python zip extract directory
Python
1 vote242 views1 answer
How to select python 3 interpreter in linux
Python
0 vote267 views2 answers
How to get current page url in django template
Python
1 vote261 views2 answers
No changes detected in app django
Python
0 vote299 views1 answer
Select Children of an Object With ForeignKey in Django?
Python Django
0 vote272 views1 answer
Promote a row in panda dataframe to header
Python
0 vote262 views1 answer
Python set class variable
Python
0 vote268 views1 answer
Python diffie hellman
Python
1 vote319 views1 answer
Module turtle has no forward member
Python
0 vote365 views1 answer
Can u length a dictionary in python
Python