/C++/The program must enter a natural number n from the console and find the number previous to n that is not divisible by 2 , 3 and 5 .

The program must enter a natural number n from the console and find the number previous to n that is not divisible by 2 , 3 and 5 .

#include <bits/stdc++.h>
using namespace std;
//use c++ 17
int main(){
    int n;
    cin>>n;
    for(int i =n-1;;i--){
    	if(i%2!=0 && i%3!=0 && i%5!=0){
    		cout<<i;
    		break;
		}
	}
	return 0;
}

Similar codes

2 votes120 views4 answers
Bubble Sort
C++
0 vote118 views1 answer
Void does not a name a type in cpp
C++
-2 votes64 views1 answer
2d array
C++
0 vote109 views1 answer
The number of ones int bitset
C++
2 votes116 views1 answer
Pbds in c++
C++
36 votes115 views4 answers
C++ hello world program
C++
0 vote104 views2 answers
Find a member variable in a vector of objects cpp
C++
0 vote101 views1 answer
Find maximum contiguous Sub arrays
C++
2 votes62 views1 answer
Read int from file c++
C++
0 vote108 views1 answer
Check whether kth bit is 1
C++