Replace nan numpy array

Python numpy array replace nan with string

import numpy as np
l=['foo', 'bar', 'baz', np.nan]

l_new=['missing' if x is np.nan else x for x in l]

print l_new
# Result:
# ['foo', 'bar', 'baz', 'missing']

Source: stackoverflow.com

Replace nan numpy array

from numpy import *

a = array([[1, 2, 3], [0, 3, NaN]])
where_are_NaNs = isnan(a)
a[where_are_NaNs] = 0

Source: stackoverflow.com

Similar codes

5 votes329 views2 answers
Finding the format of an image in cv2
Python
22 votes330 views2 answers
Python get date tomorrow
Python
0 vote322 views3 answers
Names of all methods in class introspect pythonm
Python
1 vote324 views1 answer
How to download the captions of a youtube video
Python
1 vote328 views1 answer
Generate openai schema
Python
214 votes569 views6 answers
Python loop through dictionary
Python
0 vote316 views3 answers
Numpy.dot
Python
0 vote311 views1 answer
Chrome drivers documentation
Python
0 vote280 views1 answer
Border around dataframe in pandas
Python
0 vote316 views1 answer
Pandas get day names
Python