/TypeScript/Get url params in typescript

Get url params in typescript

import {Router, ActivatedRoute, Params} from '@angular/router';
import {OnInit, Component} from '@angular/core';

@Component({...})
export class MyComponent implements OnInit {

  constructor(private activatedRoute: ActivatedRoute) {}

  ngOnInit() {
    // Note: Below 'queryParams' can be replaced with 'params' depending on your requirements
    this.activatedRoute.queryParams.subscribe(params => {
        const userId = params['userId'];
        console.log(userId);
      });
  }

}

Source: stackoverflow.com

Similar codes

0 vote282 views2 answers
Python remove all double elements from list
TypeScript
1 vote270 views2 answers
Convert list elements to uppercase python
TypeScript
0 vote306 views4 answers
C++ sort vector of objects by property
TypeScript
0 vote282 views1 answer
Capitalize first letter of all word typescript
TypeScript
1 vote285 views2 answers
No type arguments expected for interface ListAdapter
TypeScript
0 vote266 views2 answers
Object map of the http parameters mutually exclusive with fromString
TypeScript
0 vote272 views1 answer
Dart check if variable is list
TypeScript
0 vote269 views3 answers
Cahokia mounds pictures
TypeScript
0 vote293 views1 answer
Css how to create gradients on text stroke
TypeScript
-1 vote259 views1 answer
Angular input change event datatype typescript
TypeScript