Even in python

How to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))

Source: javatpoint.com

Odd or even in python

n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")

Python even or odd

injd = int(input('Enter a number'))
n = injd % 2
if n > 0:
  print('This is an odd number')
else:
  print('This is an even number')

Even in python

if (num % 2) == 0:

Similar codes

0 vote349 views1 answer
Start of my python career
Python
0 vote344 views1 answer
Rounding a number high up
Python
0 vote339 views1 answer
Python if in list multiple
Python
0 vote357 views1 answer
Python plot draw the goal line
Python
16 votes323 views5 answers
Add two dataframes together
Python
0 vote343 views1 answer
Python variables in multiline string
Python
-2 votes346 views2 answers
Save turtle programming python
Python
40 votes346 views3 answers
Train dev test split sklearn
Python
11 votes332 views4 answers
Macos set default python version
Python
0 vote382 views1 answer
Pandas to latex table width pylatex
Python