/Shell/Bash/Start multiple bash processes and wait for all to complete

Start multiple bash processes and wait for all to complete

#!/bin/bash

FAIL=0

echo "starting"

./sleeper 2 0 &
./sleeper 2 1 &
./sleeper 3 0 &
./sleeper 2 0 &

for job in `jobs -p`
do
echo $job
    wait $job || let "FAIL+=1"
done

echo $FAIL

if [ "$FAIL" == "0" ];
then
echo "YAY!"
else
echo "FAIL! ($FAIL)"
fi

Source: stackoverflow.com

Similar codes

1 vote333 views1 answer
Rename heroku app local
Shell/Bash
0 vote321 views1 answer
How to open fileexplorer from terminal in ubuntu
Shell/Bash
0 vote310 views1 answer
Ping command output to null in linux
Shell/Bash
49 votes331 views6 answers
Npm install dev dependencies
Shell/Bash
17 votes338 views6 answers
Pip upgrade all packages
Shell/Bash
0 vote359 views1 answer
Filter in powershell Win32_NTEventlogFile
Shell/Bash
41 votes318 views4 answers
Refusing to merge unrelated histories git
Shell/Bash
32 votes361 views2 answers
Install from tar gz file unix
Shell/Bash
0 vote338 views2 answers
Permission denied (publickey,keyboard-interactive).
Shell/Bash
0 vote403 views1 answer
Enable telnet ec2
Shell/Bash