/Shell/Bash/Start multiple bash processes and wait for all to complete

Start multiple bash processes and wait for all to complete

#!/bin/bash

FAIL=0

echo "starting"

./sleeper 2 0 &
./sleeper 2 1 &
./sleeper 3 0 &
./sleeper 2 0 &

for job in `jobs -p`
do
echo $job
    wait $job || let "FAIL+=1"
done

echo $FAIL

if [ "$FAIL" == "0" ];
then
echo "YAY!"
else
echo "FAIL! ($FAIL)"
fi

Source: stackoverflow.com

Similar codes

0 vote229 views1 answer
Include nsis plugin in install.nsh
Shell/Bash
1 vote227 views1 answer
Chmod read only command in linux
Shell/Bash
0 vote217 views1 answer
Error ppa.launchpad.net/certbot/certbot/ubuntu focal Release
Shell/Bash
0 vote237 views1 answer
Install dynamic library gd2
Shell/Bash
0 vote225 views1 answer
Conda install netcdf4
Shell/Bash
0 vote228 views1 answer
Linux get recursive directory size
Shell/Bash
5 votes255 views5 answers
Stop nginx
Shell/Bash
0 vote235 views1 answer
Centos zip folder
Shell/Bash
15 votes232 views5 answers
Switch php version
Shell/Bash
0 vote221 views1 answer
Purge apache 2
Shell/Bash