/C++/How to pass an array by reference in C++

How to pass an array by reference in C++

Passing array to function c++ pointer

void generateArray(int *a, int si)
{
    for (int j = 0; j < si; j++)
        a[j] = rand() % 9;
}

int main()
{
    const int size=5;
    int a[size];

    generateArray(a, size);

    return 0;
}

Source: stackoverflow.com

Array reference argument

template<typename T, size_t N>
void foo(T (&bar)[N])
{
    // use N here
}

Source: stackoverflow.com

How to pass an array by reference in C++

void func (int arr[])
{
  for(int i=0;i<arr.size();i++)
    arr[i]=1;
}
int main()
{
	int arr[100];
  	func(arr);
}

How to pass arrays by reference c++

#include <iostream>
using namespace std;
void show( int *num) {
   cout<<*num;
}
int main() {
   int a[] = {3,2,1,6,7,4,5,0,10,8};
   for (int i=0; i<10; i++) {
      show (&a[i]);
   }
   return 0;
}

-1

Source: tutorialspoint.com

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