Django reverse

from django.urls import reverse

def myview(request):
    return HttpResponseRedirect(reverse('arch-summary', args=[1945]))

Source: docs.djangoproject.com

Django reverse

return HttpResponseRedirect(reverse('blogIndex', args=[str(pk)]))

Django reverse lazy

class NewJobCBV(LoginRequiredMixin, CreateView):
    template_name = 'company/job.html'
    form_class = newJobForm
    # success_url = reverse_lazy('newJob')

    def get_success_url(self, **kwargs):
        return reverse("newJob")

-2

Source: stackoverflow.com

Similar codes

1 vote212 views1 answer
Accessing index of dataframe python
Python
1 vote211 views1 answer
Multidimensional Java Array
Python
1 vote274 views1 answer
Redirected but the response is missing a Location: header.
Python
0 vote200 views1 answer
How to put my graph in tkinter interface
Python
74 votes193 views6 answers
Clear screen python
Python
0 vote189 views10 answers
Python
Python
5 votes205 views4 answers
Python int to binary string
Python
0 vote198 views1 answer
Timedelta
Python
21 votes186 views10 answers
How to print in python
Python
1 vote230 views1 answer
Django filter by date range
Python Django