Python time range monthly

>>> from datetime import datetime, timedelta
>>> from collections import OrderedDict
>>> dates = ["2014-10-10", "2016-01-07"]
>>> start, end = [datetime.strptime(_, "%Y-%m-%d") for _ in dates]
>>> OrderedDict(((start + timedelta(_)).strftime(r"%b-%y"), None) for _ in xrange((end - start).days)).keys()
['Oct-14', 'Nov-14', 'Dec-14', 'Jan-15', 'Feb-15', 'Mar-15', 'Apr-15', 'May-15', 'Jun-15', 'Jul-15', 'Aug-15', 'Sep-15', 'Oct-15', 'Nov-15', 'Dec-15', 'Jan-16']

Source: stackoverflow.com

Similar codes

0 vote276 views1 answer
Calculate angle between 3 points python
Python
0 vote277 views1 answer
Taking a list of strings as input, our matching function returns the count of the number of strings whose first and last chars of the string are the same. Also, only consider strings with length of 2 or more. python
Python
0 vote275 views1 answer
Remove prefix in python 3.6
Python
0 vote290 views1 answer
How to encode hexadecimal python
Python
0 vote283 views1 answer
Unshorten url python
Python
0 vote290 views1 answer
Video steganography using python
Python
1 vote273 views1 answer
Dataframe describe in pandas problems
Python
11 votes291 views5 answers
Poetry python
Python
9 votes273 views5 answers
How to drop the index column in pandas
Python
5 votes285 views3 answers
How to print a message in python
Python