Permcheck codility python

def solution(A):

    A = sorted(A)
    ans = 1

    for i in range(0, len(A)):
        if A[i] == ans:
            ans += 1
        else:
            break

    if ans == len(A)+1:
        return 1
    return 0

Similar codes

0 vote373 views1 answer
Django list view
Python Django
0 vote358 views3 answers
Outliers removal
Python
1 vote336 views1 answer
Openai gym conda
Python
0 vote370 views1 answer
How to install ffmpeg python heroku
Python
0 vote333 views1 answer
Python subtract months from date
Python
0 vote371 views1 answer
How to customize simplejwt error response message in django restframework
Python
-1 vote325 views1 answer
Endgame
Python
18 votes348 views3 answers
Dataframe check for nan in iterrows
Python
40 votes358 views6 answers
Reset index pandas
Python
0 vote372 views1 answer
Plot bar chart python with resulting numbers
Python